3x^2-5/3x=-7/2x

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Solution for 3x^2-5/3x=-7/2x equation: 



3x^2-5/3x=-7/2x

We move all terms to the left:

3x^2-5/3x-(-7/2x)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



We get rid of parentheses

3x^2-5/3x+7/2x=0

We calculate fractions


3x^2+(-10x)/6x^2+21x/6x^2=0

We multiply all the terms by the denominator


3x^2*6x^2+(-10x)+21x=0

We add all the numbers together, and all the variables

3x^2*6x^2+21x+(-10x)=0

Wy multiply elements

18x^4+21x+(-10x)=0

We get rid of parentheses

18x^4+21x-10x=0

We do not support expression: x^4

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